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(Solved): Show that from (a)(AAx)[F(x)^(^())S(x)]->AAy[M(y)->W(y)] (b)(EEy)[M(y)^(^())notW(y)] the concl ...

Show that from
(a)(AAx)[F(x)^(^())S(x)]->AAy[M(y)->W(y)]
(b)(EEy)[M(y)^(^())notW(y)]
the conclusion (AAx)[F(x)->notS(x)] follows

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