AgI(s) + (1/2)Br2(g) AgBr(s) + (1/2)I2(s), H deg = 54.0 kJH deg f for AgBr(s) = 100.4 kJ/molH deg f for Br2(g) = +30.9 kJ/molThe value of H deg f for AgI(s) is

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AgI(s) + (1/2)Br2(g)  AgBr(s) + (1/2)I2(s), H deg  = 54.0 kJH deg f for AgBr(s) = 100.4 kJ/molH deg f for Br2(g) = +30.9 kJ/molThe value of H deg f for AgI(s) is

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Expert Answer to - AgI(s) + (1/2)Br2(g)  AgBr(s) + (1/2)I2(s), H deg  = 54.0 kJH deg f for AgBr(s) = 100.4 kJ/molH deg

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Solution for - AgI(s) + (1/2)Br2(g)  AgBr(s) + (1/2)I2(s), H deg  = 54.0 kJH deg f for AgBr(s) = 100.4 kJ/molH deg

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This an additional answer to - AgI(s) + (1/2)Br2(g)  AgBr(s) + (1/2)I2(s), H deg  = 54.0 kJH deg f for AgBr(s) = 100.4 kJ/molH deg

(Solved): AgI(s) + (1/2)Br2(g) AgBr(s) + (1/2)I2(s), H\deg = 54.0 kJH\deg f for AgBr(s) = 100.4 kJ/molH\deg ...

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